Author: Julia Lawall <julia@diku.dk> It seems impossible for ov to be NULL at this point. The semantic match that finds the problem is as follows: (http://coccinelle.lip6.fr/) // @r exists@ expression E, E1; identifier f; statement S1,S3; iterator iter; @@ if ((E == NULL && …) || …) { … when != false ((E == NULL …
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